How to support PHP variables with exec command?

Question

Hello I am sending mail from php. I am fetching to address and cc address from database and storing them in one one variable. $to,$cc i need to use this in mailx command. Following query is hardcoded and its working.

 exec('echo "hey i am there" | mailx -S smtp=10.0.8.8:25 -r [email protected] -s "Alert" [email protected]');

Need to replace

 $message = hey i am there
 [email protected]
 $from [email protected] 
 $subject = Alert

exec('echo $message | mailx -S smtp=10.0.8.8:25 -r $from  -s $subject $to');

But the above thing is not working

Just change ' to " like exec("echo $message | mailx -S smtp=10.0.8.8:25 -r $from -s $subject $to"); — Thamilhan
– Thamilhan, Commented May 17, 2016 at 11:46
There's two good answers now, please accept one of them so other people can benefit from them! — Loek
– Loek, Commented May 17, 2016 at 12:02
@Loek i am getting error as below smtp-server: 501 5.1.3 Invalid address — Tejas Masurkar
– Tejas Masurkar, Commented May 17, 2016 at 12:16

Thamilhan · Accepted Answer · 2016-05-17 11:50:00Z

4

Just change ' to " like

exec("echo $message | mailx -S smtp=10.0.8.8:25 -r $from  -s $subject $to");

answered May 17, 2016 at 11:50

Thamilhan

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1 Comment

iainn Over a year ago

I'd recommend adding some calls to escapeshellarg as well

Loek · Accepted Answer · 2016-05-17 11:53:27Z

2

You should concatenate your strings.

exec('echo ' . $message . ' | mailx -S smtp=10.0.8.8:25 -r ' . $from . ' -s ' . $subject . ' ' . $to);

edited May 17, 2016 at 11:53

answered May 17, 2016 at 11:48

Loek

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1 Comment

apokryfos Over a year ago

You missed the $message

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