Python: Selenium to simulate onclick

Question

I am trying to use python to play a simple javagame that I made for a class assignment. I am trying to make python open up a webpage and use the form buttons to input numbers. I think this is close to what I need but I am not sure how to fix line 7

(li = browser.find_element_by_css_selector('#button-one li:predict.input.value += 1'))

from selenium import webdriver

url = 'http://alexcassell.com/javagame'

browser = webdriver.Firefox()
browser.get(url)
li = browser.find_element_by_css_selector('#button-one li:predict.input.value += 1')
li.click()

Button-one is the ID of the first button.

Florent B. · Accepted Answer · 2016-04-15 17:30:25Z

1

You CSS selector is not valid. Try this one instead:

li = browser.find_element_by_css_selector('#button-five')

Note that you can get a CSS selector in your browser by inspecting the element and clicking on "Copy unique selector" in the context menu.

answered Apr 15, 2016 at 17:30

Florent B.

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Ferro Fang · Accepted Answer · 2016-04-15 17:47:28Z

0

try:

li = browser.find_element_by_css_selector('input#button-one[onclick="predict.input.value += 1"]')

or without element name "input":

li = browser.find_element_by_css_selector('#button-one[onclick="predict.input.value += 1"]')

or if there is only element whose "id" is "button-one", simply write:

li = browser.find_element_by_css_selector('#button-one')

answered Apr 15, 2016 at 17:47

Ferro Fang

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