PHP Select Option from Array list

Question

im new to PHP and im trying this stuff for hours, I wanted to show the Array items to the Select Option. Here's the code:

<select name="state">
         <?php
          $arrstate=array
          (
             array("AK","Alaska"),
             array("AL","Alabama"),
             array("AR","Arkansas"),
             array("AZ","Arizona"),
             array("CA","California"),
             array("CO","Colorado"),
             array("CT","Connecticut"),
             array("DC","District of Columbia"),
             array("DE","Delaware"),
             array("FL","Florida"),
             array("GA","Georgia"),
             array("HI","Hawaii"),
             array("IA","Iowa"),
             array("ID","Idaho"),
             array("IL","Illinois"),
             array("IN","Indiana"),
             array("KS","Kansas"),
             array("KY","Kentucky"),       
          );
          for($lop=0;$lop<=49;$lop++)
              {
                if (strtoupper($lead_info['state'])==$arrstate[$lop][0])
              {
                echo "<option selected=\"selected\" value=\"".$arrstate[$lop][0]."\">".$arrstate[$lop][1]."</option>\n";           
              }else{
              echo "<option value=\"".$arrstate[$lop][0]."\">".$arrstate[$lop][1]."</option>\n";           
              }
              }
          ?>
        </select>

But it seems it only shows ".$arrstate[$lop][1]." What seems to be the problem?

I wanted to know what state the user was. Before this page. There was a pre-reg that only gets his/her ZIP. and I wanted to show what state he/she currently on based on the ZIP he entered. — Kiel
– Kiel, Commented Apr 7, 2016 at 2:37
you can do a condition on option.. for example <option <?=($value == $current_zip_entered ? "selected" : "")?> > — Sam Teng Wong
– Sam Teng Wong, Commented Apr 7, 2016 at 2:40

vdhoangson · Accepted Answer · 2016-04-07 02:54:55Z

3

try it

<?php
  $arrstate = array
  (
     'AK' => 'Alaska',
     'AL' => 'Alabama',
     'AR' => 'Arkansas',
     'AZ' => 'Arizona'   
  ); ?>
<select>
     <?php foreach($arrstate as $key => $value) { ?>
      <option value="<?php echo $key; ?>"  <?=($value == $current_zip_entered ? "selected" : "" )?>><?php echo $value; ?></option>
     <?php } ?></select>

answered Apr 7, 2016 at 2:54

vdhoangson

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Sam Teng Wong · Accepted Answer · 2016-04-07 03:19:46Z

0

  <?php
      $arrstate=array
      (
         "AK","Alaska",
         "AL","Alabama",
         "AR","Arkansas",
         "AZ","Arizona"   
      );
   ?>

this is the easiest way...

   <select>
         <?php
           foreach($arrstate as $key => $value) {
         ?>
          <option value="<?php echo $key; ?>"  <?=($value == $current_zip_entered ? "selected" : "" )?>><?php echo $value; ?></option>
         <?php
           }
          ?>
   </select>

edited Apr 7, 2016 at 3:19

answered Apr 7, 2016 at 2:36

Sam Teng Wong

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Dimitris Maniatis · Accepted Answer · 2018-09-21 10:06:08Z

0

You can retrieve from database like this example:

      <select>
         <?php $result = mysqli_query($conn, "SELECT * FROM categories");
              while ($row = mysqli_fetch_array($result)) {                                
                    $categories = array($row["category"]);
                    $arrlength = count($categories);

                    for($x = 0; $x < $arrlength; $x++) {
                       echo  "<option>";
                       echo  $categories[$x]; 
                       echo  "</option>";
                                         }}?>
               </select>

edited Sep 21, 2018 at 10:06

answered Sep 21, 2018 at 9:38

Dimitris Maniatis

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