Python parse int from string

Question

test1 = 'name1'
test2 = 'name2'
..
test3 = 'name45'
test4 = 'name1231231'

Let's say I have bunch of strings which start with 'name' and are followed by a number of any length.

How can I parse out the number in the string?

Is regex the only way or is there a built-in module that can accomplish this task?

I did not downvote but perhaps your post was downvoted because of one of these reasons — Bhargav Rao
– Bhargav Rao, Commented Mar 14, 2016 at 16:57
Loop over all of them, replace name and cast int() or float() on them. — jhoepken
– jhoepken, Commented Mar 14, 2016 at 16:57
its pretty clear, and there is research via regex, how is it not useful? this can be helpful to others — ealeon
– ealeon, Commented Mar 14, 2016 at 17:00
If you have the strings like this test=['name1','name2','name123125'] you can get just the integers like this: ints = [int(n[4:]) for n in test] — avip
– avip, Commented Mar 14, 2016 at 17:02

Martin Evans · Accepted Answer · 2022-10-13 09:33:09Z

36

In Python 3, you could do the following:

import string

for test in ['name1', 'name2', 'name45', 'name1231231', '123test']:
    print(int(test.strip(string.ascii_letters)))

Giving you:

string.ascii_letters gives you a string containing all upper and lowercase letters. Python's strip() function takes a string specifying the set of characters to be removed, which in this case is all alpha characters, thus leaving just the numbers behind.

Note: This would not be suitable for a string such as 123name456.

If there are just known common prefixes/suffixes to all strings, the following approach could also be used in Python 3.9:

for test in ['name1', 'name2', 'name45', 'name1231231', '123test']:
    print(test.removeprefix('name').removesuffix('test'))

edited Oct 13, 2022 at 9:33

answered Mar 14, 2016 at 17:00

Martin Evans

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Robᵩ · Accepted Answer · 2016-03-14 17:06:53Z

5

If you know that the prefix is name, then you can either remove just that string, or you can skip the first four letters, like so:

s = 'name123'
print int(s.replace('name',''))

s = 'name123'
print int(s[4:])

answered Mar 14, 2016 at 17:06

Robᵩ

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