Undefined returned when trying to parse json array

Question

I a php array I converted to json and echoed that I want to retrieve using jquery. The echoed json is in the format:

[{"id":"1","title":"Test Event 1","description":"This is the first test event","location":"Acme Hall, Room 101","contact":"John Smith","url":"http:\/\/www.example.com","start":"2016-02-29 13:00:00","end":"2016-02-29 14:00:00"},
{"id":"2","title":"Test Event 2","description":"This is the second test event","location":"Venable Hall, Room 101","contact":"Jane Smith","url":"http:\/\/www.example.com","start":"2016-03-08 09:00:00","end":"2016-03-10 10:45:00"},
{"id":"3","title":"Test Event 3","description":"This is the third test event","location":"Sitterson Hall, Room 200","contact":"Jane Smith","url":"http:\/\/www.example.com","start":"2016-03-18 15:00:00","end":"2016-02-22 16:30:00"}]

When I attempt to use Ajax GET to parse and display the JSON, 'undefined' is returned. My ajax code is:

$.ajax({
    type: 'GET',
    url: 'get-events.php',
    dataType: "json",
    cache: false,
    success: function (result) {
        alert(result[start]);
    },
});

UPDATE:

Thanks for the responses. I finally got it sorted using

for (var key in result) {
 if (result.hasOwnProperty(key)) {
     result[key].id

   }
  }

What is the variable start?

epascarello
– epascarello

2016-02-29 14:12:50 +00:00
Commented Feb 29, 2016 at 14:12 — epascarello
– epascarello, Commented Feb 29, 2016 at 14:12

HenriC · Accepted Answer · 2016-02-29 14:09:21Z

1

Your result is a table, so you have to specify the index: result[index]

Then, json is a {"key" : "value"} format, where key is a string. In your code you used start which is an undefined variable.

So you should try:

alert(result[0]["start"]);

answered Feb 29, 2016 at 14:09

HenriC

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Comments

Philipp · Accepted Answer · 2016-02-29 14:08:35Z

0

It seems you don't use the result value the correct way. Result is an array of objects. If you want to access the start value of the first element, you have to use result[0].start.

To access all values, you should use a for-loop to loop over the array.

for (var i = 0; i < result.lenght; i++) {
    // result[i].start
}

answered Feb 29, 2016 at 14:08

Philipp

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