I have this code:
num = int(input("Enter a number: ")
if num%2 == 0:
print("The number is even")
else:
print("The number is odd")
Why do I get a syntax error on the if statement line?
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Does this answer your question? Why do I get a SyntaxError (or an IndentationError) in a line with perfectly valid syntax?Karl Knechtel– Karl Knechtel2023-11-25 21:45:22 +00:00Commented Nov 25, 2023 at 21:45
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2 Answers
num = int(input("Enter a number: "))
if num%2 == 0:
print("The number is even")
else:
print("The number is odd")enter code here
Missing a ) on the line before. Lots of times when you get syntax errors on a line it happens at that line or a line or a few lines before that, in your case it's looking for a matching paren.
1 Comment
FallenRune
Whoops, didn't notice that, thanks for the quick response!
As stated by @mikeb, the error in on the previous line, where
num = int(input("Enter a number: ") should be
num = int(input("Enter a number: ")).
When you are looking for an error, always check the previous line as well.
