javascript return null or None if parameter is not given to function

Question

I am new to javascript and this is my function:

var now = any(function(result){
    console.log(result);

})


function any(gone){
    return gone
}

console.log(now)

but if I give it params like var now = any(function(result){ it returns me tada.. what I want is it should take default value null or None like in python and if the value is not provide it should give null or None

function any(gone=null) somthing like this.. after that I want to receive callback in result

"now" is a function instead of the return value of that function — Kit Fung
– Kit Fung, Commented Feb 1, 2016 at 6:29
What is the expected result? What should be logged, which value should now get? — Bergi
– Bergi, Commented Feb 1, 2016 at 6:37
Prior to ECMAScript 2015 you must test the value of parameters and assign values based on the outcome, see MDN: Default parameters — RobG
– RobG, Commented Feb 1, 2016 at 6:41
Please state clearly the problem you are trying to solve, or the desired behavior you hope to achieve. — user663031
– user663031, Commented Feb 1, 2016 at 7:15

void · Accepted Answer · 2016-02-01 06:29:40Z

1

function any(gone){

   gone = gone || null;

}

And in ES6 you can do

function any(gone = whatever){

       gone = gone || null;

}

answered Feb 1, 2016 at 6:29

void

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2 Comments

varad Over a year ago

doing null it gives me [Function] as response

RobG Over a year ago

Though you might want a more explicit test like if (typeof gone == 'undefined') since any(0) or any(false) likely should not replace the value with null.

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