How to assign Command line arguments to Variables in Shell Script

Question

I am trying to assign the command line parameters to a variable (Entire argument to one variable) in shell script but it is not working Here is what I tried:

str1 ='$*'
str1 ="$*"
set str1 =$*
set str1 ="$*"
set str1 ='(echo $*)'
set str1 ='$*'

Why there is a space between the variable and the assignment operator (=)? You need some basics first. Try this, it talks about some of the basics of the basics. — Jahid
– Jahid, Commented Jan 28, 2016 at 12:33
unix.stackexchange.com/questions/32290/… would be a good duplicate but it was migrated. — tripleee
– tripleee, Commented Jan 28, 2016 at 13:37

Chris Maes · Accepted Answer · 2016-01-28 11:17:29Z

1

If you want to get one variable containig all arguments; use $@:

str1="$@"

answered Jan 28, 2016 at 11:17

Chris Maes

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4 Comments

tripleee Over a year ago

But note that this breaks the special semantics of "$@" - there is no way for an argument to contain a space, for example. In modern shells, use an array instead. This is a massive FAQ.

Ahmad Over a year ago

Hello Chris, I tried that as well but no luck. if I remove "set" it says command not found, without "set" I don't get error but nothing is assigned

Chris Maes Over a year ago

do you put this in a script? How do you use this? What output do you get? What do you expect? There are many questions like this around...

tripleee Over a year ago

See stackoverflow.com/questions/12711786/…

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