How to return multiple objects when passing two array arguments

Question

I have a method in java let say:

public List<Data> getData(String[] str, Integer[] num, String ss);

I have to pass two array and a non-array arguments as shown above, this method returns List of objects of type Data.

Now, the question is how to create a list of objects which contain every possible combination of elements of the array.

i.e : Object with elements :

getData(String[0] str, Integer[0] num, String ss);
getData(String[0] str, Integer[1] num, String ss);
getData(String[1] str, Integer[0] num, String ss);
getData(String[1] str, Integer[1] num, String ss);

Any clue will be appreciated.

Use nested loop. Sorry I'm not going to write you a code because this looks very much like a homework and you should be doing your research. If you ask what's nested loop then we're happy to help — gerrytan
– gerrytan, Commented Dec 2, 2015 at 11:28

Ross Drew · Accepted Answer · 2015-12-02 11:36:19Z

2

Create a List<Data> inside your method then loop through one array

for (String s: str)

then for each element in that array, loop through the other array, this is called a nested loop

for (Integer i : num)

Then create a Data object for each combination and add to a List<Data>

 for (String s: str){
    for (Integer i : num){
       //TODO Add new Data(s,i,ss) to list
    }
 }

answered Dec 2, 2015 at 11:36

Ross Drew

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2 Comments

Shamim Ahmad Over a year ago

Thanks, One more condition is what if either of the two arrays are empty (having no elements).

Ross Drew Over a year ago

if either is empty then the resulting data is just the non-empty array, converted to Data with nulls set to the other property.

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