I want to script updating code for my AWS Lambda using a Fabric task. Boto3 api expects a byte array of base-64 encoded zip file.
What would be the simplest way to create it assuming I have the source code files as the input?
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2 Answers
With the current boto3, don't unzip it, don't base64 encode it. You can do it with an open and a read like this:
import boto3
c = boto3.client('lambda')
c.create_function({
'FunctionName': 'your_function',
'Handler': 'your_handler',
'Runtime': 'python3.6',
'Code': {'ZipFile': open('./deploy.zip', 'rb').read()}
})
I use the zip file above for getting started quickly. You can also upload the deploy.zip to a S3 bucket and pass the bucket + key as strings in the 'Code' dict as 'S3Bucket' and 'S3Key'.
2 Comments
Brian C.
FYI: I'm still using the above code with boto3 1.9.
Mrunall Veer
I used the same code, However I am getting error that No such directory
Actually boto3 documentation is out of date, you should pass the bytes directly:
https://github.com/boto/boto3/issues/201
As to the zip file this should point you in the right direction:
6 Comments
sumek
Yes, I've looked at them. They don't answer my question though. As I've mentioned I'd like to use boto create_function method that accepts a byte array of base-64 encoded zip file.
rsFF
actually IIUC you can pass the bytes directly, did you tried that?github.com/boto/boto3/issues/201
sumek
Thats useful! So the remaining part is how to zip file and then get the bytes out of it in elegant way? Ideally I was thinking about doing it all in memory without intermediary files.
rsFF
I edited the answer so it could provide the pointers necessary for you and for future reference.
garnaat
There is code in kappa that does this. Perhaps it would be useful. Specifically, checkout: github.com/garnaat/kappa/blob/develop/kappa/function.py#L121
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