Passing a dynamic variable in an array within PHP

Question

I am not sure if it's possible or not but I am trying to pass a random variable to fill an array.

Here is the code normally:-

//Loading all data of user in an array variable.
$user_fields = user_load($user->uid);
// Updated one array variable in this array.
$user_fields -> field_module_3_status['und'][0]['value'] = "Started";
// Saved back the updated user data
user_save($user_fields);

But I want to provide the variable field_module_3_status dynamically through a variable.

Hence suppose I have $user_field_name = field_module_3_status.

So what I tried to do is:-

$user_fields = user_load($user->uid);

$this_users_status = $user_fields -> $user_field_name;

$this_users_status['und'][0]['value'] = "Started";

user_save($user_fields);

Unfortunately this doesn't work.

Any idea how I can achieve this?

$val; $ref =& $val; $val = 0; /*ref is 0 now*/ $val = 't'; /*ref is 't' now*/ this could help you along your path. EDIT: reversed &= — x13
– x13, Commented Nov 20, 2015 at 0:16
Thanks a lot. I tried something like this and it worked perfectly. — Steve
– Steve, Commented Nov 20, 2015 at 0:27

Barmar · Accepted Answer · 2015-11-20 00:22:06Z

1

You're making a copy of the array when you do the assignment to $this_users_status. You need to assign to the array in the object property.

$user_fields->{$user_field_name}['und'][0]['value'] = "Started";

Or you could use a reference:

$this_users_status =& $user_fields->$user_field_name;

answered Nov 20, 2015 at 0:22

Barmar

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