Jquery .each using array objects for arguments

Question

I have an array...

var dataFilesArray =  [
   {data1: argumentA, file1: argumentB},
   {data2: argumentA, file2: argumentB}
   ]

For each data/file pair in the array, I would like to pass both values as arguments to function useData.

$.each(dataFilesArray {
   function useData (argumentA, argumentB)
});

Next loop would be for data2/file2, and so on until end of array.

function useData (argumentA, argumentB)

Can $.each be used this way?

Using

var dataFilesArray = [
    {data1: "someurl.com", file1: "somefileName.jpg"},
]

T.J. Crowder · Accepted Answer · 2015-03-19 13:09:56Z

2

It's nothing to do with $.each, it's just what you put in the callback you give it:

$.each(dataFilesArray, function(index, entry) {
    useData(entry.data, entry.file);
});

Note I used data and file above; you wouldn't want the property names in each object in your array to be different, so the array would be:

var dataFilesArray =  [
   {data: argumentA, file: argumentB},
   {data: argumentA, file: argumentB}
   ];

If they're really going to be data1/file1 for the first entry, data2/file2 for the next, etc., you can do that, but it's a very odd structure and it's delicate — if you change the contents of the array, you have to change all those names. But for completeness:

$.each(dataFilesArray, function(index, entry) {
    var num = index + 1;
    useData(entry["data" + num], entry["file" + num]);
});

answered Mar 19, 2015 at 13:09

T.J. Crowder

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4 Comments

Jai Over a year ago

they're really part is just awesome.

Jotter Over a year ago

I am getting a RESOURCE_NOT_FOUND error. The data is urls and filenames. The urls are good.

T.J. Crowder Over a year ago

@Jotter: The above works, there must be an issue applying it to your code.

Jotter Over a year ago

You're right. It works. But I see your point, having the numbered names is not a good idea. Since they are pairs and I want to iterate them as such.

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