String str[] = new String[3];
Can someone explain to me the memory map for the above line. How many objects and ref it will have?
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4 Answers
That line allocates one object, which is an array of three String references. These references are initialized to null by default.
It also defines str as a local variable holding a reference to an array of Strings. It initializes the variable with a reference to that object it just created.
So you have this diagram:
str (local variable)
+--------+ array object
| -----+---------> +-------------+
+--------+ | null | (can hold a reference to a String)
+-------------+
| null | (can hold a reference to a String)
+-------------+
| null | (can hold a reference to a String)
+-------------+
answered Feb 25, 2015 at 7:57
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new String[3] will create one object, array of 3 String references, initialized with nulls. Object size (for 32-bit JVM) = header(8) + length(4) + 3 references (4 bytes each)
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It will Have one Array instance with the reference of 3 String objets.
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Also, noticing that you are probably new to this(might just be a typo, sorry if I am wrong), a correction to your post. The correct syntax in your code snippet should be
String[] str = new String[3];
