'tuple' has no attribute. OpenCV Python

Question

I am trying to pass a window over an image so I can get the average b,g,r pixel values inside the window (not really sure how to do this).

At the moment I am trying to get a window to pass over my image but on line 17 I get the error:

Traceback (most recent call last):
  File "C:\Python27\bgr.py", line 17, in <module>
    pt2=(pt1.x+5,pt1.y+5)
AttributeError: 'tuple' object has no attribute 'x'

Any ideas?

Here is my code:

# import packages
import numpy as np
import argparse
import cv2
import dateutil
from matplotlib import pyplot as plt

bgr_img = cv2.imread('images/0021.jpg')
height, width = bgr_img.shape[:2]

#split b,g,r channels
#b,g,r = cv2.split(bgr_img)

for i in range(0,height):
  for j in range(0,width):
    pt1=(i,j)
    pt2=(pt1.x+5,pt1.y+5)
    point.append([pt1,pt2])
    cv2.rectangle(bgr_img,pt1,pt2,(255,0,0))

#cv2.imshow('image',bgr_img)          
#cv2.waitKey(0)

Thanks in advance :)

jonrsharpe · Accepted Answer · 2015-02-18 13:56:27Z

2

This line:

pt1 = (i, j)  # I have added spaces per the style guide

assigns a new tuple object to the name pt1 (see the docs, the tutorial). Tuples do not, by default, have an x or y attribute. You either need to access the first and second items in the tuple by index:

pt2 = (pt1[0] + 5, pt1[1] + 5)  # note 0-based indexing

or to create a collections.namedtuple, which allows you to define attributes:

from collections import namedtuple

Point = namedtuple("Point", "x y")

pt1 = Point(i, j)
pt2 = Point(pt1.x + 5, pt1.y + 5)

That being said, as i and j are still in scope, the easiest thing to do would be simply:

pt1 = (i, j)
pt2 = (i + 5, j + 5)

and even if they weren't still in scope you could unpack pt1 (whether tuple or namedtuple), and use the separate x and y:

x, y = pt1
pt2 = (x + 5, y + 5)

edited Feb 18, 2015 at 13:56

answered Feb 18, 2015 at 13:49

jonrsharpe

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Comments

Mark R. · Accepted Answer · 2015-02-18 13:46:42Z

0

Because pt1 is a tuple and doesn't have x or y attributes . You probably want:

pt2 = (pt1[0] + 5, pt1[1] + 5)

answered Feb 18, 2015 at 13:46

Mark R.

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Comments

syntonym · Accepted Answer · 2015-02-18 13:51:28Z

0

You are trying to access an x attribute in pt1, but pt1 is a tuple and tuple have no x attribute. You could either

Write a Custom Point class
Use a named tuple

The second solution could look like the following:

from collections import namedtuple
Point = namedtuple('Point', ['x', 'y'])
p1 = Point(i,j)
p2 = (pt1.x+5,pt1.y+5)

answered Feb 18, 2015 at 13:51

syntonym

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Comments

PM 2Ring · Accepted Answer · 2015-02-18 13:56:49Z

You can't access plain tuples like that, you need to change

pt2=(pt1.x+5,pt1.y+5)

to

pt2=(pt1[0] + 5, pt1[0] + 5)

However, Python does have a namedtuple which can be accessed via attributes; there's even a Point namedtuple example in the docs.

Here's a small example derived from the docs I linked to:

#!/usr/bin/env python

from collections import namedtuple

Point = namedtuple('Point', ['x', 'y'])

p = Point(11, y=22)     # instantiate with positional or keyword arguments

print p[0] + p[1]       # indexable like the plain tuple (11, 22)

x, y = p                # unpack like a regular tuple
print x, y
print p.x + p.y         # fields also accessible by name

print repr(p)           # readable __repr__ with a name=value style
print tuple(p)

output

33
11 22
33
Point(x=11, y=22)
(11, 22)

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