How to read a csv file script Python?

Question

import csv
with open('some.csv', 'rb') as f:
  reader = csv.reader(f)
  for row in reader:
     print row

gives this error

python2 test.py 
Traceback (most recent call last):
File "test.py", line 1, in <module>
import csv
File "/home/miruss/virtualbox/csv.py", line 4, in <module>
  f = open(sys.argv[1], 'rt')
IndexError: list index out of range

the reason for the error do not understand.

You might want to edit your post with the code fragments that are necessary to reproduce the problem. — Ron
– Ron, Commented Dec 1, 2014 at 23:15

Meitham · Accepted Answer · 2014-12-01 23:15:31Z

2

Your error comes from "sys.argv[1]".

You meant to execute your code against the file name.

python2 test.py filename.csv

answered Dec 1, 2014 at 23:15

Meitham

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2 Comments

Joran Beasley Over a year ago

good job for actually seeing that his question really had nothing to do with csv ...

Alter Miruss Over a year ago

python2 test.py some.csv Traceback (most recent call last): File "test.py", line 1, in <module> import csv File "/home/miruss/virtualbox/csv.py", line 6, in <module> reader = csv.reader(f) AttributeError: 'module' object has no attribute 'reader'

Joran Beasley · Accepted Answer · 2014-12-01 23:14:50Z

0

print list(csv.reader(open("somefile.csv")))

would work I think

answered Dec 1, 2014 at 23:14

Joran Beasley

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