Adding functions to an array

Question

This code adds functions to an array :

    var fArr = []
    fArr.push(test())
    fArr.push(test())

    function test(){
        console.log('here')
    }

However the function test() is invoked each time its added to array fArr

Can the function test() be added to the array fArr without invoking the function ?

I'm attempting to populate the array fArr with functions and then iterate over fArr and invoke the functions, not invoke the functions as they are being added to fArr which is current behavior.

fiddle : http://jsfiddle.net/3fd83oe1/

test() is executing your function, just do .push(test)

juvian
– juvian

2014-11-19 18:08:36 +00:00
Commented Nov 19, 2014 at 18:08 — juvian
– juvian, Commented Nov 19, 2014 at 18:08

Ethan Brown · Accepted Answer · 2014-11-19 18:08:00Z

6

Yes, you can add functions to an array. What you're actually doing is invoking the functions and adding the result of the function invocation to the array. What you want is this:

fArr.push(test);
fArr.push(test);

answered Nov 19, 2014 at 18:08

Ethan Brown

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Comments

Nabil Kadimi · Accepted Answer · 2014-11-19 18:15:22Z

2

It's as simple as:

fArr.push(test, test);

Examples

var fArr = []

function test() {
    return 'here';
}


fArr(test, test);     
// > Array [ function test(), function test() ]
// Because test evaluates to itself

fArr(test(), test());
// > Array [ "here", "here" ]
// Because test() evaluates to 'here'

edited Nov 19, 2014 at 18:15

answered Nov 19, 2014 at 18:09

Nabil Kadimi

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1 Comment

Ethan Brown Over a year ago

+1 for reminding us that Array.prototype.push takes multiple arguments.

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