Python: How to create 2D array using existing lists

Question

I have been trying to resolve this issue.

I have 3 lists

dev = ['Alex', 'Ashley', 'Colin']
phone = ['iPhone', 'Nexus', 'Nokia']
carrier = ['ATT', 'T-Mobile', 'MegaFon']

Is this a pythonic way to create a new 2D array like this:

matrix = [['Alex', 'iPhone', 'ATT'], ['Ashley','Nexus','T-Mobile'], ['Colin', 'Nokia', 'MegaFon']]

Thank you

Alok Singhal · Accepted Answer · 2014-10-15 23:05:31Z

2

I think you want:

>>> zip(dev, phone, carrier)
[('Alex', 'iPhone', 'ATT'),
 ('Ashley', 'Nexus', 'T-Mobile'),
 ('Colin', 'Nokia', 'MegaFon')]

See zip documentation.

If you need a list of lists (instead of a list of tuples in Python 2, or an iterator in Python 3), use Padraic's suggestion: [list(x) for x in zip(dev, phone, carrier)].

edited Oct 15, 2014 at 23:05

answered Oct 15, 2014 at 22:50

Alok Singhal

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2 Comments

Padraic Cunningham Over a year ago

[list(x) for x in zip(dev,phone,carrier)] to get a lists of lists

Alok Singhal Over a year ago

Thanks @PadraicCunningham. Your method also works as requested for Python 3 (where zip returns an iterator). Updated my answer.

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