PHP how to pass a variable-length function parameters to another variable length function?

Question

I have two functions with an optional amount of variables:

function getTexts()
{
  $this->printTextToDashboard();
}

function printTextToDashboard()
{
  $args = func_get_args();
  $argsNum = count($args);
  for($i=0; $i < $argsNum; $i++)
  {
    echo "This is the $i text: "."<br />".$args[$i]."<br />";
  }
}

For instance I want to call getTexts like this:

getTexts($name, $lastname, $email);

I know it has something to do with user_func_* , but I'm unable to implement it.

Thanks in advance

u_mulder · Accepted Answer · 2014-09-27 10:36:06Z

2

Something like this should work:

function getTexts()
{
    call_user_func_array(array($this, 'printTextToDashboard'), func_get_args());
}

answered Sep 27, 2014 at 10:36

u_mulder

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1 Comment

bwoebi Over a year ago

or, in php 5.6 (and above): $this->printTextToDashboard(...func_get_args());

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