Java Multidimensional Arrays

Question

I am in the process of learning Java and am very confused on multidimensional arrays. When I say this I don't mean the array syntax but more so the logic of using arrays with for statements. What I am wondering is how do I incorporate arrays into for statements correctly and what does all of the code in play do, and why is it there. Here is some code I have been working on (based off a tutorial) and was wondering if someone could fully explain everything that is going on.

package tutorial;

public class apples {
public static void taco(String[] args) {
    int firstarray[][]={{8,9,10,11},{12,13,14,15}};
    int secondarray[][]={{30,31,32,33},{43},{4,5,6}};

    System.out.println("This is the first array");
    display(firstarray);

    System.out.println("This is the second array");
    display(secondarray);
}

public static void display(int x[][]) {
    for (int row=0;row<x.length;row++) {
        for (int column=0;column<x[row].length;column++) {
            System.out.println(x[row][column]+"\t");
        }
        System.out.println();
    }
}

So what I don't understand is the entire

public static void display(int x[][]) {
    for (int row=0;row<x.length;row++) {
        for (int column=0;column<x[row].length;column++) {
            System.out.println(x[row][column]+"\t");

If someone could explain that in more depth that would be great. I get for statements and arrays in general, im just confused with how this works.

since you have no problem with declaring and initializing 2d array , so you are asking about display method, it loops through every element in the matrix ( each element is 1d array), how can you print every element in 1d array ? using another loop (nested loop) to print every element in the array ( length of the first array is count of arrays in matrix, length of each array is array.length) ) — user1935024
– user1935024, Commented Aug 17, 2014 at 19:49

Eran · Accepted Answer · 2014-08-17 19:49:35Z

1

You can look at a two dimensional array int x[][] as an array whose elements are themselves arrays of int.

Therefore, x has x.length int array elements, and each of them is an int array of x[row].length ints.

answered Aug 17, 2014 at 19:49

Eran

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Comments

Kabir Peshawaria · Accepted Answer · 2015-09-23 06:15:15Z

When you declare an array like this:

int arr[][]={{8,9,10,11},{12,13,14,15}};

You're pretty much declaring an array with 2 rows and 4 columns. Visually it makes sense to think of it like this:

{8,9,10,11}

{12,13,14,15}

Then when you try to access a certain element, think of the top leftmost element as [0][0].

So arr[0][0] would equal 8.

I find it easiest to think of multi dimensional arrays not just as rows/columns, but also as x and y. Except it's a little tricky because it's counter-intuitive in the sense the format is:

arr[y_coordinate][x_coordinate].

as you move from 8 to the right, the x coordinate increases.

as you move from 8 downwards, the y coordinate increases.

So, to access 9, you could use arr[0][1]. To access 12, you could use arr[1][0].

Now on to the method you'd like explained:

public static void display(int x[][]) {
    for (int row=0;row<x.length;row++) {
        for (int column=0;column<x[row].length;column++) {
            System.out.println(x[row][column]+"\t");

x.length returns the number of rows, or y coordinates, your multi-d array has.

x[row].length returns the number of columns, or x coordinates, a particular row index has.

What this method does is it starts at the top y coordinate (the first row), and then it checks how many columns/x coordinates that row has. It then loops through those x coordinates in that row from left to right printing its value. When it has finished printing all the values in a row, it moves on to the next row!

On a side note, I would edit your display method ever so slightly to:

 public static void display(int x[][]) {
    for (int row=0;row<x.length;row++) {
        for (int column=0;column<x[row].length;column++) {
            System.out.print(x[row][column]+"\t");
        }
        System.out.println();
    }
}

I changed a System.out.println to System.out.print

why? Because then it only prints a new line for the next row.

Let me know if any part of this is unclear.

Community · Accepted Answer · 2017-05-23 11:51:47Z

the following method

public static void display(int x[][]) {
    for (int row=0;row<x.length;row++) {
        for (int column=0;column<x[row].length;column++) {
            System.out.println(x[row][column]+"\t");
        }
    }
}

is similar to the following method

public static void display(int x[][]) {
    //x is an array with two dimensions, so its elements are arrays with one dimension
    for (int row=0;row<x.length;row++) {
        //x.length returns the count of all stored arrays in the array x
        int[] rowArray_ = x[row];//x[row] is an array with one dimension
        for (int column=0;column<rowArray_.length;column++) {
            System.out.println(rowArray_[column]+"\t");
        }
    }
}

@Cole Riggle: in your code, you have:

int secondarray[][]={{30,31,32,33},{43},{4,5,6}};

so secondarray is componed of three arrays which are:

{30,31,32,33}
{43}
{4,5,6}

so in your static method, you process on the arrays in the following order

{30,31,32,33}
{43}
{4,5,6}

I hope you will understand my explanation.

If not, see multidimensional-arrays-lengths-in-java

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