json_decode is not returning proper php array of api response with curl call

Question

I am working on the shipping API for one of my client. I have the shipping api from the vendor. On making curl request in json format, the json response is not converted into php array? Find the code below:

$params['format'] = 'json';
$params['data'] =json_encode($package_data);
$token = "xxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxx";
$url = "http://test.shipping.co/push/json/?token=".$token;

$ch = curl_init();
curl_setopt($ch, CURLOPT_URL, $url);
curl_setopt($ch, CURLOPT_POST, true);
curl_setopt($ch, CURLOPT_POSTFIELDS,http_build_query($params));
curl_setopt($ch, CURLOPT_HTTPHEADER, array('Content-Type: application/x-www-form-urlencoded'));
$result = curl_exec($ch);
curl_close($ch);
print_r($result);
$results = json_decode($result, true);
print_r($results);

Here I have 2 print_r function, and following is the output:

{ "cash_pickups_count": 1.0, "cod_count": 0, "success": true, "package_count": 1, "upload_wbn": "UPL21969440", "replacement_count": 0, "cod_amount": 0.0, "prepaid_count": 0, "pickups_count": 0, "packages": [ { "status": "Success", "waybill": "0008110000125", "refnum": "8", "client": "demo", "remarks": "", "cod_amount": 21841.0, "payment": "Cash" } ], "cash_pickups": 21841.0 }1

1

I am receiving 2 output as : 1

I want to access the array in php of this response. I tried json_decode() but it is not responding properly. Need your inputs here. Thanks in advance.

hindmost · Accepted Answer · 2014-08-11 07:45:45Z

5

The problem is that you haven't set CURLOPT_RETURNTRANSFER option. In this case CURL outputs response directly into STDOUT (browser) and curl_exec returns true. Because of this json_decode cannot decode $result variable (since it has value = true).

So you have to set CURLOPT_RETURNTRANSFER option:

$ch = curl_init();
curl_setopt($ch, CURLOPT_URL, $url);
curl_setopt($ch, CURLOPT_RETURNTRANSFER, true);
curl_setopt($ch, CURLOPT_POST, true);
curl_setopt($ch, CURLOPT_POSTFIELDS,http_build_query($params));
curl_setopt($ch, CURLOPT_HTTPHEADER, array('Content-Type: application/x-www-form-urlencoded'));
$result = curl_exec($ch);
curl_close($ch);
print_r($result);
$results = json_decode($result, true);
print_r($results);

answered Aug 11, 2014 at 7:45

hindmost

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shailendra pathak · Accepted Answer · 2014-09-08 12:47:51Z

1

you forgot to add this

curl_setopt($ch, CURLOPT_RETURNTRANSFER, true);

answered Sep 8, 2014 at 12:47

shailendra pathak

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Comments

Samar Haider · Accepted Answer · 2014-08-11 05:39:55Z

0

Please try this below one

$results = json_decode(file_get_contents('php://input'), true);

instead of

$results = json_decode($result, true);

answered Aug 11, 2014 at 5:39

Samar Haider

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4 Comments

Tarunn Over a year ago

its giving me same error. I am still unable to get the php array. Any other method I can get this response in php and process the results?

Tarunn Over a year ago

After adding this, only difference in output was that 1 as an output was not coming. Only the response was printed in $results.

Samar Haider Over a year ago

what php version are you using?

Samar Haider Over a year ago

$result = '{ "cash_pickups_count": 1.0, "cod_count": 0, "success": true, "package_count": 1, "upload_wbn": "UPL21969440", "replacement_count": 0, "cod_amount": 0.0, "prepaid_count": 0, "pickups_count": 0, "packages": [ { "status": "Success", "waybill": "0008110000125", "refnum": "8", "client": "demo", "remarks": "", "cod_amount": 21841.0, "payment": "Cash" } ], "cash_pickups": 21841.0 }'; $results = json_decode($result, true); test this if its not printing desired output than may b you have problem in json_decode function

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