regex parsing a string to extract numbers in shell script

Question

How can i parse the string below to extract version number and release number from the filename string below.

program-product_3.0.1009-5-XY1.0.456-1_i386.deb

Here I'm interested in getting

Version number : 3.0.1009
Release number : 5

I tried grep, awk and sed and I`m not able to get it quite right.

The string follows the pattern,

Filename_Version-Release-OtherDependentPackageNameAndVersion-Release_Arch.deb.

Please note that the naming convention is out of my control.

konsolebox, The naming pattern does not change. I meant that the current pattern is fixed and I cant change it to fit my needs. That was just a preemptive statement in case someone suggested it. — Rijin
– Rijin, Commented Aug 15, 2014 at 19:59

anubhava · Accepted Answer · 2014-08-07 16:58:25Z

3

Using pure BASH:

s='program-product_3.0.1009-5-XY1.0.456-1_i386.deb'
[[ "$s" =~ _([^-]+)-([^-]+) ]] && echo "${BASH_REMATCH[1]} : ${BASH_REMATCH[2]}"
3.0.1009 : 5

edited Aug 7, 2014 at 16:58

answered Aug 7, 2014 at 16:50

anubhava

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4 Comments

anubhava Over a year ago

Yes sure. First it matches an underscore then it finds ([^-]+) which will grab 3.0.1009 in input. Then it matched hyphen and captures ([^-]+) that will find 5

Rijin Over a year ago

Thanks. But I decided to go with the awk version though.

anubhava Over a year ago

Sure that's your choice but storing output of awk into 2 different BASH variables is another extra operation. Here you get these values in BASH variables.

Rijin Over a year ago

No argument there. But readability trumps brevity always (at least for me). When working with large code bases worked on by hundreds of developers, in fast paced agile project like mine, we go out of our way to spell out what is happening so that code is very easy to understand and errors can be caught easily. So I always go for commonly used/popular/easily readable solutions even if it means a slight performance hit or few extra lines of code. And often, this philosophy is enforced on us during review :)

Cole Tierney · Accepted Answer · 2014-08-07 17:43:08Z

2

Here's an awk version:

awk -F'[_-]' '{print "Version number : "$3; print "Release number : "$4}'

answered Aug 7, 2014 at 17:43

Cole Tierney

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Comments

konsolebox · Accepted Answer · 2014-08-07 17:14:05Z

0

With early bash version 2.05b or newer:

#!/bin/bash
F='program-product_3.0.1009-5-XY1.0.456-1_i386.deb'
IFS=- read V R __ <<< "${F#*_}"
printf 'Version number : %s\nRelease number : %s\n' "$V" "$R"

Run with:

bash script.sh

Output:

Version number : 3.0.1009
Release number : 5

answered Aug 7, 2014 at 17:14

konsolebox

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