Java how to sort string array based on order values were placed?

Question

How can I sort an array and print the values in descending order?

say the example array is: ["1a","1b","1c"]

they have numbers before the first character alphabet values, i want to print:

1c
1b
1a

If it's a question of printing only, you might as well sort and then loop from last index to first when printing. — shree.pat18
– shree.pat18, Commented Jul 1, 2014 at 7:24
well its kinda specific to the pattern of the strings i need to do this with and they are being added in different orders. — user3792817
– user3792817, Commented Jul 1, 2014 at 7:26

ThatGuy343 · Accepted Answer · 2014-07-01 07:23:17Z

4

What you are asking is to sort an array in reverse order.

Basically you do this by reversing Arrays.sort() which is ascending.

String [] testArray = {"1a", "1b", "1c"};

Arrays.sort(testArray, Collections.reverseOrder());

for (String str : testArray) {
    System.out.println(str);
}

Output is,

1c
1b
1a

You can test this here, https://ideone.com/q1OGBD.

answered Jul 1, 2014 at 7:23

ThatGuy343

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