Ruby - Unable to count the array values?

Question

I have a program :

Question : Input a number of integer of 2 digit only , and in the out-put it should show the all input values BUT loop should stop on 42 :

example

input

1 2 87 42 99

output

1 2 87

my code

  a = []
 5.times do |i| 
  a[i] =  Integer(gets.chomp)
 end
 a.each do |e|
   break if e == '42'
  puts e
 end

BroiSatse · Accepted Answer · 2014-04-25 11:21:03Z

1

Few things to change. First of all gets will give you a string together with \n at the end, so you need to change it to gets.chomp to remove it.

Now your loop should look like this:

a.each do |e|
  break if e == '42'
  puts e
end

However ruby's array has much butter function which is perfect for what you want:

puts a.take_while {|e| e != '42'}

Additional notes:

Note that it is operating on strings rather than numbers. You might need to validate the input at some point and convert it into integer values.
5.times do|i| - the |i| bit is obsolete.

answered Apr 25, 2014 at 11:21

BroiSatse

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3 Comments

bindi bhatt Over a year ago

I ma getting the answer same as the input.i have edited my code have a look

bindi bhatt Over a year ago

how to validate in input for accepting only 2 digit ?

BroiSatse Over a year ago

@bindibhatt - yes, when Yyou convert input to integer you need to change '42' to 42. TO validate input you simply need to check whether you got 2 digits or not. I don't know the requirements so you need to decide what to do in such a case. You can check the format of the input with if input =~ /\A\d{1,2}\z/.

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