PHP - fill array same value

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[Solved]

I want create array consist 40 elements (10x values "c", 10x values "d", 10x values "h", 10x values "s"). I try create array:

$znaczki = array_fill(0, $iloscZnaczkow, 'c');
$znaczki = array_fill($iloscZnaczkow, $iloscZnaczkow, 'd');
$znaczki = array_fill((2 * $iloscZnaczkow), $iloscZnaczkow, 'h');
$znaczki = array_fill((3 * $iloscZnaczkow), $iloscZnaczkow, 's');

Var $IloscZnaczkow contains number - 10. Unfortunetlly, later I will use $znaczki and script

$i = 0;
foreach ($serializ as $key => $value) {
    echo '<img src="images/' . $value . $znaczki[$i] . '.gif" />';
    $i++;
}

throw image src="images/11.gif" (it doesn't have $znaczki[$i] everywhere :()

I mean where has OP defined this variable ? AS far as I'm concerned this variable could be an array as much as it could be a cheese pizza... Can OP please var_dump() all variables ? — bastienbot
– bastienbot, Commented Feb 9, 2014 at 15:06

kojiro · Accepted Answer · 2014-02-09 15:09:39Z

5

The problem is you keep overwriting the array:

$znaczki = array_merge(
    array_fill(0, $iloscZnaczkow, 'c'),
    array_fill(0, $iloscZnaczkow, 'd'),
    array_fill(0, $iloscZnaczkow, 'h'),
    array_fill(0, $iloscZnaczkow, 's')
);

is what you want. You don't really need the index math anymore, as array_merge will maintain the indices for you.

answered Feb 9, 2014 at 15:09

kojiro

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