Pass multiple parameters in Html.BeginForm MVC4 controller action

Question

I have something like this:

   public ActionResult ImageReplace(int imgid,HttpPostedFileBase file)
    {
        string keyword = imgid.ToString();
        .......
    }

and in my .cshtml:

   @model Models.MemberData
   @using (Html.BeginForm("ImageReplace", "Member", FormMethod.Post,
            new { imgid = @Model.Id, enctype = "multipart/form-data" }))
        { 
     <input type="file" name="file" id="file" value="Choose Photo"  /> 
     <input type="submit" name="submit" value="Submit" />
    }

here the value of imgid is not passing to controller action. show an error,The parameters dictionary contains a null entry for parameter 'imgid' of non-nullable type 'System.Int32' for method 'System.Web.Mvc.ActionResult ImageReplace

p.s.w.g · Accepted Answer · 2014-01-06 04:25:17Z

27

Use this overload, which allows you to distinguish between route values and HTML attribtues:

@using (Html.BeginForm(
        "ImageReplace", "Member", 
        new { imgid = @Model.Id }, 
        FormMethod.Post,
        new { enctype = "multipart/form-data" }))
{ 
    <input type="file" name="file" id="file" value="Choose Photo"  /> 
    <input type="submit" name="submit" value="Submit" />
}

answered Jan 6, 2014 at 4:25

p.s.w.g

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1 Comment

sergiol Over a year ago

I think you mean this overload: BeginForm(HtmlHelper, String, String, RouteValueDictionary, FormMethod, IDictionary<String,Object>) learn.microsoft.com/en-us/dotnet/api/…

Dimitar Dimitrov · Accepted Answer · 2014-01-06 04:26:11Z

4

You can also pass imgid as a field in the form, something like:

@model Models.MemberData
@using (Html.BeginForm("ImageReplace", "Member", FormMethod.Post,
        new { enctype = "multipart/form-data" }))
{ 
   @Html.HiddenFor(x => x.Id)
   <input type="file" name="file" id="file" value="Choose Photo"  /> 
   <input type="submit" name="submit" value="Submit" />
}

answered Jan 6, 2014 at 4:26

Dimitar Dimitrov

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Comments

user1968030 · Accepted Answer · 2014-01-06 04:28:29Z

3

Use this:

      @using (Html.BeginForm("ImageReplace", "Member",   
      new { imgid = @Model.Id },   FormMethod.Post,
  new { enctype = "multipart/form-data" }))

answered Jan 6, 2014 at 4:28

user1968030

Comments

Muhammad Armaghan · Accepted Answer · 2019-09-16 07:22:56Z

0

    @using (Html.BeginForm("Search", "Orders", FormMethod.Post, htmlAttributes: new { id = "example-form", @class = "app-search" }))
       {

           <input type="text" class="form-control" name="OrderNo" style="max-width:100% !important" placeholder="Search OrderNo"> 
            <a class="srh-btn">
             <i class="ti-close"></i>
            </a>
           </input>

       }

  public ActionResult Search(FormCollection form)
        {
            string Orderno = form["OrderNo"];
            int orderno = Convert.ToInt32(Orderno);

            return View(orderno );
        }

edited Sep 16, 2019 at 7:22

answered Sep 14, 2019 at 22:22

Muhammad Armaghan

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