I wrote a condition with regex str.matches("\\D+") read with Scanner but on entering char+digit this test fails for example 3x or e3 but it should not happen.
It should pass any non digit occurrence anywhere in the string even if its a symbol.
4 Answers
If m is a Matcher, then m.matches returns true only if the entire string matches the pattern. If you want to just check whether some part of the string matches, you can use m.find instead of m.matches. (Note: I'm not sure whether that's actually the problem you're having.)
atleast once a non digit occurrence should be there thats what i'm saying, should pass
How about this
.*\D.*
You can test it here.
2 Comments
MxLDevs
The non-digit occurrence should occur anywhere, which means you can have anything else before or after.
+, 1+, +1, 1+1. You would just replace .* with the appropriate regex if .* is too broad.
Prashant
A good source to read regex, since most of the articles do not split up the examples and explain.
This call fails to match 3e since:
str.matches("\\D+")
is same as:
str.matches("^\\D+$")
Because String#matches takes given regex and matches the complete input.
To make sure there is at least one non-digit, you should better use this lookahead based regex:
str.matches("(?=\\d*\\D).*")
Where (?=\\d*\\D) is positive lookahead that makes sure there is at least 1 non-digit in the given input.
Comments
\D matches any non-numeric character, so of course it will fail if you pass it a string with digits in it.
If you want to match only characters and numbers you could do something like:
matches("[a-zA-Z0-9"]+);
1 Comment
Prashant
i just want to pass a non digit occurrence anywhere in the string even if it is a symbol.
\Dis a non-digit character.