converting regular expression in PHP to javascript

Question

I have the following PHP regex:

/\b([A-Z0-9]{8})\b/i

in which I wanted to convert to a javascript regex. So I tried the following:

/^(\b([A-Z0-9]{8})\b/i

however it failed. Why is this? I am trying to check if a string has a word that contains 8 digit of alphanumeric character, ignoring uppercase and lowercase (meaning that 2HJS1289 and 2hjs1289 should match). The string needs to have 8 digits.

define "it failed". what did you test, what happened? Anyway, I see 2 open brackets ((), and only one closeing? — Nanne
– Nanne, Commented Dec 4, 2013 at 10:57

Michael · Accepted Answer · 2013-12-04 10:57:32Z

2

You're missing a ):

/^(\b([A-Z0-9]{8})\b)/i

Although, you can just use the same expression as you would for PHP.

answered Dec 4, 2013 at 10:57

Michael

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jogesh_pi · Accepted Answer · 2013-12-04 10:59:24Z

1

var regex = /^(\b([A-Z0-9]{8})\b)/i;
var _string = "2HJS1289";

if( regex.test(_string) ){
    alert('pass');
}
else{
    alert('fail');
}

http://jsfiddle.net/jogesh_pi/2A4tA/

answered Dec 4, 2013 at 10:59

jogesh_pi

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