Jquery to PHP array transfer

Question

Ok, I know there were many of those but my code just won't work... I tried solutions found on Stack but still...

I would like to transfer my array built in jQuery to my php script that will compare it with other array etc.

My jQuery code looks like this:

$.post('rezultat.php',{wyb: JSON.stringify(wybrane)});

and in my rezultat.php file I try to decode it:

$wyb = json_decode($_POST['wybrane']);

I tried the $_POST method before, with no results. What am I doing wrong?

$_POST['wyb'], since that's what you're calling the field in the JS code. var_dump($_POST) will confirm that. — Marc B
– Marc B, Commented Nov 18, 2013 at 16:17

OlivierH · Accepted Answer · 2013-11-18 16:18:45Z

3

You need to use $_POST['wyb'] instead of $_POST['wybrane'] in your php script, since you used 'wyb' key in the array you created in javascript.

answered Nov 18, 2013 at 16:18

OlivierH

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Ramchandra Apte · Accepted Answer · 2013-11-18 16:41:07Z

0

You are calling the parameter with his Javascript name, try to call with the $_POST name:

$wyb = json_decode($_POST['wyb']);

edited Nov 18, 2013 at 16:41

Ramchandra Apte

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answered Nov 18, 2013 at 16:21

Neoligero

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5 Comments

Austin Mullins Over a year ago

Why was this voted down when it's essentially the same as the answer above?

user3005435 Over a year ago

Yeah, I tried that already. On my page I receive this: Notice: Undefined index: wyb in C:\xampp\htdocs\rezultat.php on line 3 where line 3 is of course $wyb = json_decode($_POST['wyb']);

Neoligero Over a year ago

Check your param before send, console.log(JSON.stringify(wybrane)); and var_dump($_POST) in the other side and check your values.

user3005435 Over a year ago

Does it matter that wybrane array is empty at first? User will fill it with his own values and finally hit the button in jQuery that will start the function that sends it to php file. So technically, when I load the site, this array is empty, right?

user3005435 Over a year ago

You mean sth like this: if(isset($_POST['wyb'])){ $wyb = json_decode($_POST['wyb']); foreach($wyb as $w) { echo $w; }} ? Cause it doesn't work. Sorry if I'm retarded :)

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