Javascript ( jQuery ) Error: SyntaxError: missing ) after argument list

Question

I have a simple javascript/jquery function:

jQuery(document).ajaxSuccess(function(e, xhr, settings) {
   var widget_id_base = '099_cf_samurai_widget';

   if(settings.data.search('action=save-widget') != -1 &&
        settings.data.search('id_base=' + widget_id_base) != -1) {
         my_function_chosen_o99();
   }
}); 

function my_function_chosen_o99(){
   jQuery(".chzn-select").chosen();
}

Which works correctly, but when I add the width parameter:

function my_function_chosen_o99(){
   jQuery(".chzn-select").chosen(width:'95%');
}

It gives me an error:

Error: SyntaxError: missing ) after argument list
Source File: http://localhost/my-path/js/o99.chosen.init.js?ver=k99
Line: 20, Column: 41
Source Code:
      jQuery(".chzn-select").chosen(width:"95%"); 
.............................................|

What is wrong with this code?

It is related to a javascript syntax error

Arun P Johny
– Arun P Johny

2013-11-13 15:51:10 +00:00
Commented Nov 13, 2013 at 15:51 — Arun P Johny
– Arun P Johny, Commented Nov 13, 2013 at 15:51

Arun P Johny · Accepted Answer · 2013-11-13 15:50:13Z

9

You need to pass an object as the argument(within {})

 jQuery(".chzn-select").chosen({width:'95%'});

answered Nov 13, 2013 at 15:50

Arun P Johny

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4 Comments

Obmerk Kronen Over a year ago

Thank you dear sir ... But why ?? I just followed the official documentation found here : harvesthq.github.io/chosen/options.html . is the documentation wrong ? I mean the problem is resolved , but I would really want to learn the reason :-)

Arun P Johny Over a year ago

@ObmerkKronen looks like there is a typo in that documentation

Obmerk Kronen Over a year ago

oh .. ok . Thanks. so for future reference - I ALWAYS need to pass options in that manner {} ??

Arun P Johny Over a year ago

@ObmerkKronen it depends on the function... but if it is an settings object then yes

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