Finding a pattern inside a string in Python

Question

I am new to Python.

I have a string printing a table(and its contents) just like the following

Name         At time Last  Inter\ Max    Logfile Location               Status  
                     time   val   log                                           
                           (mins) files                                         
------------ ------- ----- ------ ------ ------------------------------ ------- 
foo1           now   16:00   60   100    flash:/schedule/foo1/          Job     
                                                                        under   
                                                                        progress
foo2           now     -     60   100    -                              Waiting 
tech-support   now   16:00   60   100    flash:/schedule/tech-support/  Job     
                                                                        under   
                                                                        progress

I need to find how many times the string "Job under progress" is present in the table. I tried len( re.findall( pattern, string ) ) and len( re.findall("(?=%s)" % pattern, string) ) but none of them seem to work.

Any better suggestions?

Is that the exact format? Is the line Job under progress (in one line), rather than broken up in three lines as in your example? — Burhan Khalid
– Burhan Khalid, Commented Oct 28, 2013 at 6:19
If I am not wrong its one line. Whole row is inserted using table.newRow(..) — Prasoon Saurav
– Prasoon Saurav, Commented Oct 28, 2013 at 6:21

thefourtheye · Accepted Answer · 2013-10-28 06:27:45Z

3

data = """
Name         At time Last  Inter\ Max    Logfile Location               Status  
                     time   val   log                                           
                           (mins) files                                         
------------ ------- ----- ------ ------ ------------------------------ ------- 
foo1           now   16:00   60   100    flash:/schedule/foo1/          Job     
                                                                        under   
                                                                        progress
foo2           now     -     60   100    -                              Waiting 
tech-support   now   16:00   60   100    flash:/schedule/tech-support/  Job     
                                                                        under   
                                                                        progress
                                                                        """
import re
print len(re.findall("Job\s+under\s+progress", data))

Output

Edit: If its in the same line, you dont need regEx at all

data = """
Name         At time Last  Inter\ Max    Logfile Location               Status  
                     time   val   log                                           
                           (mins) files                                         
------------ ------- ----- ------ ------ ------------------------------ ------- 
foo1           now   16:00   60   100    flash:/schedule/foo1/          Job under progress
foo2           now     -     60   100    -                              Waiting 
tech-support   now   16:00   60   100    flash:/schedule/tech-support/  Job under progress
"""

print sum(1 for line in data.split("\n") if "Job under progress" in line)

Output

edited Oct 28, 2013 at 6:27

answered Oct 28, 2013 at 6:21

thefourtheye

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2 Comments

Eevee Over a year ago

picky, but i would use + here.

thefourtheye Over a year ago

@Eevee You are right. There will be atleast one whitespace character.

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