accessing constructor name from prototype function in javascript

Question

Is it possible to do the following:

function A() {}
function B() {}
B.prototype = A;
function C() {}
C.prototype = A;

A.prototype.myname = function() { /* get 'B' or 'C' here */ }

so that when I for example call B.myname() I will have the name 'B' available in the function body?

Trying this.constructor.name as expected just returns 'A' every time.

How do you mean? What I actually want to do is customize the method so that it will behave differently depending on how it is called. — kliron
– kliron, Commented Oct 4, 2013 at 20:17
Your function declarations have syntax errors, remove the =! Then, Why use a function as the prototype? — bfavaretto
– bfavaretto, Commented Oct 4, 2013 at 20:19

bfavaretto · Accepted Answer · 2013-10-04 20:28:09Z

1

I suppose you're looking for this?

function A() {}
A.prototype.myname = function() {
    return this.constructor.name;   
};
function B() {}
B.prototype = new A();
B.prototype.constructor = B;
var b = new B();
console.log(b.myname()); // logs B

http://jsfiddle.net/BFxnb/

answered Oct 4, 2013 at 20:28

bfavaretto

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