how to pass a array from ajax to php with some other variable

Question

Guys i want to pass an array (got from checkbox) with some other variable.

function some_function(user_id,add_remove_id,which_page) {
    //getting the array
    var allVals = [];   
    $('#friend_id_saf :checked').each(function() {
        allVals.push($(this).val());
    });
    var type=3;
    var data = 'user_id=' + user_id+'&add_remove_id='+add_remove_id+'&type='+type;

    $.ajax({
        type:"POST",
        url:"add_rem_friend.php", 
        //*****************************************
        // how should i send the data to php
        data:data,{myarray:allVals}, 
        //******************************************          
        success:function(html) {
            if (which_page==='incoming-request') {
                $('#'+add_remove_id).html(html);

            } else if(which_page ==='profile-details') {
                $('#div_status').html(html);
            }
        }
    });

    return false;
}

how should i send the array with other data?

data:data,{myarray:allVals},

please help me.

Convert your array to a JSON string - stackoverflow.com/questions/191881/… — Styphon
– Styphon, Commented Jul 1, 2013 at 13:08
$('#friend_id_saf :checked').each(function() { seems you're using duplicate ID's, ID's should be unique! — tymeJV
– tymeJV, Commented Jul 1, 2013 at 13:10
I guess you can refer to this SO, stackoverflow.com/questions/5377585/…. — dreamweiver
– dreamweiver, Commented Jul 1, 2013 at 13:10
instead of merging them like this var data = 'user_id=' + user_id+'&add_remove_id='+add_remove_id+'&type='+type; , better place them all in ajax call like this .data:{'user_id':user_id,'add_remove_id':add_remove_id,'type':type,'myArray:'allVals'}. this is simplest way of passing the values in ajax call. — dreamweiver
– dreamweiver, Commented Jul 1, 2013 at 13:15
@MDTAHMIDHOSSAIN:Sorry man, i told you the wrong way. try this way data: { start: 'value1', end: 'value 2' }. let me know if you are still getting error — dreamweiver
– dreamweiver, Commented Jul 2, 2013 at 10:04

Nix · Accepted Answer · 2013-07-01 13:09:09Z

1

I think its as simple as just merging the maps.

data: $.extend(data, {myarray:allVals});

or if its simple set it before the call and just pass data.

#before .ajax
data[myarray] = allVals

#inside of .ajax
data: data

answered Jul 1, 2013 at 13:09

Nix

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1 Comment

MD TAHMID HOSSAIN Over a year ago

data: $.extend(data, {myarray:allVals}); should be in ajax call?

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