How to parse a JSON Array which have no array name

Question

I have a json array which have no array name. How can I parse a JSON array which dont have a name? This is my array

[
{
    "id": "13",
    "email": "[email protected]",
    "first_name": "jcheck",
    "last_name": "check",
    "country": "india",
    "city": "tvm",
    "zip_code": "695581",
    "phone": "4712584632",
    "status": "Success"
}
]

I tried to convert it to JSON object and also tried to get the String straightly from the array. But I got exceptions both time.

JSONArray array = new JSONArray(json) and then JSONObject object = jsonArray.getJSONObject(i); — Muhammad Babar
– Muhammad Babar, Commented Jun 17, 2013 at 9:45

Blackbelt · Accepted Answer · 2013-06-17 09:50:37Z

7

JSONArray array = new JSONArray(yourString);
JSONObject obj = array.JSONObject(0)

if you have more than one object:

int size = array.length();
for (int i = 0; i < size; i++) {
   JSONObject obj = array.JSONObject(i);
}

edited Jun 17, 2013 at 9:50

answered Jun 17, 2013 at 9:44

Blackbelt

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2 Comments

Pankaj Kumar Over a year ago

I am not getting JSONObject as JSONOBject and you got to many upvotes also.......... and another haven't single one. Is this fixed IPL? :D

Jashan PJ Over a year ago

@ Pankaj Kumar. I tried to set your answer, but you deleted it. :(, thanks to blackbelt also.

Lazy Ninja · Accepted Answer · 2013-06-17 09:45:52Z

2

Why not use

    JSONArray array = new JSONArray(jsonString);
    for (int i = 0; i < array.length(); i++)
    {
        JSONObject obj= array.getJSONObject(i);

        String id = obj.getString("id");
        String email = obj.getString("email");
}

answered Jun 17, 2013 at 9:45

Lazy Ninja

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Comments

Mr.Me · Accepted Answer · 2013-06-17 09:45:12Z

0

String json = //your json array as string;
try {
JSONArray myArray = new JSONArray(json);
catch(JASONException e){
     Log.e("JSON", e.toString());
}

answered Jun 17, 2013 at 9:45

Mr.Me

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Comments

roshan posakya · Accepted Answer · 2016-07-29 12:34:57Z

0

String finaljson=buffer.toString();

            JSONArray array = new JSONArray(finaljson);

            int size = array.length();
            for (int i = 0; i < size; i++)
            {
                JSONObject j= array.getJSONObject(i);

                String Image =j.getString("Image");
                String ImageName=j.getString("Iname");
                String Rating=j.getString("Rating");
                String Description=j.getString("Description");
                return Image +"/"+ ImageName +"/"+ Rating +"/"+ Description;
            }

answered Jul 29, 2016 at 12:34

roshan posakya

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1 Comment

MTCoster Over a year ago

Can you provide an explanation of why this example is preferable compared to the existing accepted answer?

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