pass array to method Java

Simply remove the brackets from your original code.

PrintA(arryw);

private void PassArray(){
    String[] arrayw = new String[4];
    //populate array
    PrintA(arrayw);
}
private void PrintA(String[] a){
    //do whatever with array here
}

That is all.

An array variable is simply a pointer, so you just pass it like so:

PrintA(arrayw);

Edit:

A little more elaboration. If what you want to do is create a COPY of an array, you'll have to pass the array into the method and then manually create a copy there (not sure if Java has something like Array.CopyOf()). Otherwise, you'll be passing around a REFERENCE of the array, so if you change any values of the elements in it, it will be changed for other methods as well.

There is an important point of arrays that is often not taught or missed in java classes. When arrays are passed to a function, then another pointer is created to the same array ( the same pointer is never passed ). You can manipulate the array using both the pointers, but once you assign the second pointer to a new array in the called method and return back by void to calling function, then the original pointer still remains unchanged.

You can directly run the code here : https://www.compilejava.net/

import java.util.Arrays;

public class HelloWorld
{
    public static void main(String[] args)
    {
        int Main_Array[] = {20,19,18,4,16,15,14,4,12,11,9};
        Demo1.Demo1(Main_Array);
        // THE POINTER Main_Array IS NOT PASSED TO Demo1
        // A DIFFERENT POINTER TO THE SAME LOCATION OF Main_Array IS PASSED TO Demo1

        System.out.println("Main_Array = "+Arrays.toString(Main_Array));
        // outputs : Main_Array = [20, 19, 18, 4, 16, 15, 14, 4, 12, 11, 9]
        // Since Main_Array points to the original location,
        // I cannot access the results of Demo1 , Demo2 when they are void.
        // I can use array clone method in Demo1 to get the required result,
        // but it would be faster if Demo1 returned the result to main
    }
}

public class Demo1
{
    public static void Demo1(int A[])
    {
        int B[] = new int[A.length];
        System.out.println("B = "+Arrays.toString(B)); // output : B = [0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0]
        Demo2.Demo2(A,B);
        System.out.println("B = "+Arrays.toString(B)); // output : B = [9999, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0]
        System.out.println("A = "+Arrays.toString(A)); // output : A = [20, 19, 18, 4, 16, 15, 14, 4, 12, 11, 9]

        A = B;
        // A was pointing to location of Main_Array, now it points to location of B
        // Main_Array pointer still keeps pointing to the original location in void main

        System.out.println("A = "+Arrays.toString(A)); // output : A = [9999, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0]
        // Hence to access this result from main, I have to return it to main
    }
}
public class Demo2
{
    public static void Demo2(int AAA[],int BBB[])
    {
        BBB[0] = 9999;
        // BBB points to the same location as B in Demo1, so whatever I do
        // with BBB, I am manipulating the location. Since B points to the
        // same location, I can access the results from B
    }
}

Important Points

• you have to use java.util package
• array can be passed by reference

In the method calling statement

• Don't use any object to pass an array
• only the array's name is used, don't use datatype or array brackets []

Sample Program

import java.util.*;

class atg {
  void a() {
    int b[]={1,2,3,4,5,6,7};
    c(b);
  }

  void c(int b[]) {
    int e=b.length;
    for(int f=0;f<e;f++) {
      System.out.print(b[f]+" ");//Single Space
    }
  }

  public static void main(String args[]) {
    atg ob=new atg();
    ob.a();
  }
}

Output Sample Program

1 2 3 4 5 6 7

If you are too lazy ;) to declare variable.

import static org.junit.Assert.assertEquals
public class BinarySearch 
{

    public static void main(String[] args) 
    {
        search(new int[] {-1,0,3,5,9,12}, 9); //creating and passing array
    }
    public static int search(int[] nums, int target) 
    {
        //write some code
        return -1;
    }
}

This is very useful for unit test like below

assertEquals(4,search(new int[] {-1,0,3,5,9,12}, 9));
assertEquals(-1,search(new int[]{-1,0,3,5,9,12}, 2));

You got a syntax wrong. Just pass in array's name. BTW - it's good idea to read some common formatting stuff too, for example in Java methods should start with lowercase letter (it's not an error it's convention)

class test
{
    void passArr()
    {
        int arr1[]={1,2,3,4,5,6,7,8,9};
        printArr(arr1);
    }

    void printArr(int[] arr2)
    {
        for(int i=0;i<arr2.length;i++)
        {
            System.out.println(arr2[i]+"  ");
        }
    }

    public static void main(String[] args)
    {
        test ob=new test();
        ob.passArr();
    }
}

public static void main(String[] args) {

    int[] A=new int[size];
      //code for take input in array
      int[] C=sorting(A); //pass array via method
      //and then print array

    }
public static int[] sorting(int[] a) {
     //code for work with array 
     return a; //retuen array
}

In this way we can pass an array to a function, here this print function will print the contents of the array.

public class PassArrayToFunc {

    public static void print(char [] arr) {
        for(int i = 0 ; i<arr.length;i++) {
            System.out.println(arr[i]);
        }
    }

    public static void main(String[] args) {
        Scanner scan = new Scanner(System.in);
        char [] array = scan.next().toCharArray();
        print(array);
        scan.close();
    }

}