from mongodb to array with objects

Question

It must be a better way to do this? I want to get all documents from the sounds collection and output them with an array with objects in (using it for backbone.js). It cant be an object with objects in!

$sounds = iterator_to_array($db->sounds->find());

    $a = "[";

    foreach ($sounds as $id => $sound) {
        $a .= json_encode($sound) . ",";
    }

    //remove the last comma...
    $a = substr($a, 0, -1);
    $a .="]";

    echo $a;

How about echo json_encode(array_values($sounds)); ?

Leri
– Leri

2013-04-09 06:43:25 +00:00
Commented Apr 9, 2013 at 6:43 — Leri
– Leri, Commented Apr 9, 2013 at 6:43
yea! this works great! could you explain what it does?

tobbe
– tobbe

2013-04-09 06:51:36 +00:00
Commented Apr 9, 2013 at 6:51 — tobbe
– tobbe, Commented Apr 9, 2013 at 6:51
I'll post it as answer with explanation.

Leri
– Leri

2013-04-09 06:52:08 +00:00
Commented Apr 9, 2013 at 6:52 — Leri
– Leri, Commented Apr 9, 2013 at 6:52

Leri · Accepted Answer · 2013-04-09 06:54:06Z

1

You could try:

$sounds = iterator_to_array($db->sounds->find());
echo json_encode(array_values($sounds));

array_values will return values of associated array as indexed array so json_encode will return json encoded string in a format you want (i.e. javascript array instead of javascript object).

answered Apr 9, 2013 at 6:54

Leri

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