Store output from command in variable in Bash. The output is being run instead of stored

Question

I am trying to store the output from a command in Bash in a variable, but instead of storing the output it is being interpreted as a command and run. That is not what I want.

tmp="$($line | awk '{print $1}')" This runs the output from awk as a command.

echo $line | awk '{print $1}' This prints out the output I want to store in the variable.

How can I get the output from the second line stored in a variable?

dogbane · Accepted Answer · 2013-04-05 08:05:09Z

3

You're looking for this:

tmp=$(echo "$line" | awk '{print $1}')

But that's a Useless Use of Echo. Use a here-string instead:

tmp=$(awk '{print $1}' <<< "$line")

answered Apr 5, 2013 at 8:05

dogbane

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Davide · Accepted Answer · 2013-04-05 08:04:54Z

0

This should work

var=`echo $line | awk '{print $1}'`

With the backticks

answered Apr 5, 2013 at 8:04

Davide

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