Java Inheritance - cannot find method to invoke on object?

Question

To begin with I have three classes. One called:

Temperature (superclass)
Weather (subclass superclass)
UseTemperature (subclass that holds main method)

For this program the main method is only supposed to display the temperature in Celsius and wind speed. I do not know what the issue is though..

My issue is that setWindSpeed/getWindSpeed cannot be found within UseTemperature.

//TEMPERATURE:

public class Temperature
{
    private double degrees;


    public void setDegrees (double degrees)
    {
        this.degrees = degrees;
    }


    public double getDegrees ()
    {
        return degrees;
    }

/////////////////////////////////////////////////////////////////////////////////////////
//WEATHER:

public class Weather extends Temperature
{
    private double windspeed; // Number + km/h

    private void setWindSpeed (double windspeed) //setter
    {
        this.windspeed = windspeed;
    }


    public double getWindSpeed ()  //getter
    {
        return windspeed;
    }
}
/////////////////////////////////////////////////////////////////////////////////////////
//USE TEMPERATURE:

class UseTemperature // can be public but makes no diffrence
{
    public static void main (String args[])
    {
        Temperature temp;

        temp = new Temperature ();

        temp.setDegrees (40.0);      
        temp.setWindSpeed (70.0); // NOT FOUND IN TEMPERATURE

        System.out.print (temp.getDegrees ());
        System.out.print (" degrees ");

        System.out.println (temp.getWindSpeed()); // NOT FOUND IN TEMPERATURE
        System.out.println (" km/h");

    }
}

You need to declare methods public/protected that you want to invoke elsewhere. — Omar
– Omar, Commented Feb 9, 2013 at 17:01
This is very bad use of inheritance here. It doesn't hold that weather IS_A temperature. — Jiri Kremser
– Jiri Kremser, Commented Feb 9, 2013 at 20:08

Reimeus · Accepted Answer · 2013-02-09 17:04:02Z

2

The class Temperature does not contain the methods setWindSpeed or getWindSpeed. You would need to create a Weather object and make those methods accessible to call them.

Weather myWeather = new Weather();
// set/get ...

answered Feb 9, 2013 at 17:04

Reimeus

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Comments

M Sach · Accepted Answer · 2013-02-09 17:04:20Z

0

Either you need to declare setWindSpeed/getWindSpeed in tempaerature class or do

Weather temp = new Weather ();

the reason is when you do

Temperature temp;
 temp = new Temperature ();
 temp.getWindSpeed()

compiler just see whether getWindSpeed lies inside Temperature class or not. It does not. So it gives compilation error

answered Feb 9, 2013 at 17:04

M Sach

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Comments

Shiva Kumar · Accepted Answer · 2013-02-09 17:04:29Z

0

Temperature class indeed does not have getWindSpeed and setWindSpeed methods. It is only the subclass Weather which has got those methods. Superclasses know nothing about Subclasses. Instead of creating an instance of Temperature, create that of Weather

answered Feb 9, 2013 at 17:04

Shiva Kumar

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Comments

Grim · Accepted Answer · 2013-02-09 17:07:26Z

UseTemperature is not actually extending Weather, and anyway it would not be able to access the (private) setWindSpeed method. You could access it if you were to make it a nested class (see http://docs.oracle.com/javase/tutorial/java/javaOO/nested.html for details), but it is probably not a good design option.

Instead, if UseTemperature is meant to be your application access point and never to be instantiated (like in the snippet you posted), consider changing the access modifier of setWindSpeed to something a bit more permissive, like protected or even default. That would allow you to access it from a class in the same package without having to subclass it.

Edit: also, as Reimeus pointed out, a Weather object must be instantiated instead of a Temperature one.

dejavu · Accepted Answer · 2013-02-09 17:07:35Z

0

How can you access setWindSpeed and getWindSpeed from Temperature. Remember all subclass are superclass but all superclass are not subclass. You need to define setWindSpeed and getWindSpeed in Temperature.

After defining access getWindSpeed and setWindSpeed like this.

Temperature t = new Weather();

t.setWindSpeed(); and so on.

Also don't make those method private in Weather. You can access them only when you make them public or atleast protected in Temperature.

answered Feb 9, 2013 at 17:07

dejavu

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