PHP How to pass all array's values as different arguments to a function?

Question

Let's say I have an array like this

$update = array(
  'field1' => 'one',
  'field2' => 'two',
  'field3' => 'three'
);

Then I have a function, let's say write() which accepts unlimited number of arguments like this write($thing_one,$thing_two,$thing_three,$thing_four)

So I know I can pass arguments like write($update[0],$update[1],$update[2]) but in real example I have a lot of keys and values in $update and what I want to do is find a way to pass arguments from this array to a function, so that it would be same as manually typing update($update[0],$update[1],$update[2])

I hope somebody will help me out. Thank you.

It sounds to me like you are getting confused partly because of the way you set up your applications logic. This really shouldn't be an issue as people would usually just assemble an array of parameters to pass as a whole. I suggest you reconsider your logic here (or alternatively explain it abit more so that we can give suggestions) — Lix
– Lix, Commented Nov 18, 2012 at 14:36
just set your write() function to receive one variable and then retrieve individually inside the function by means of an index — ianace
– ianace, Commented Nov 18, 2012 at 14:41
write does not accept an array. It accepts many arguments. To better understand this it is coming from mysqli class. example: $dbi->prepare("INSERT INTO table (name,surname) VALUES (?,?);")->execute('john','davids'); So I can create (name,surname) from array, and (?,?) as well, but cannot create 'john','davids' as arguments for execute function. thanks — Davit
– Davit, Commented Nov 18, 2012 at 14:42

Community · Accepted Answer · 2023-11-17 20:33:26Z

1

call_user_func_array() should do the trick nicely.

edited Nov 17, 2023 at 20:33

CommunityBot

11 silver badge

answered Nov 18, 2012 at 14:36

Niet the Dark Absol

326k86 gold badges480 silver badges604 bronze badges

Sign up to request clarification or add additional context in comments.

1 Comment

Davit Over a year ago

This does job. Thanks. $stmt = $this->dbi->prepare($sql); $stmt = call_user_func_array(array($stmt, "execute"), $args);

Tomer · Accepted Answer · 2012-11-18 14:36:32Z

0

Why not just pass the array itself to the write function:

$update = array(
  'field1' => 'one',
  'field2' => 'two',
  'field3' => 'three'
);

write($update);

answered Nov 18, 2012 at 14:36

Tomer

17.9k16 gold badges82 silver badges139 bronze badges

5 Comments

Tomer Over a year ago

since when php is type safe?

Davit Over a year ago

yes write does not accept an array. It accepts many arguments. To better understand this it is coming from mysqli class. example: $dbi->prepare("INSERT INTO table (name,surname) VALUES (?,?);")->execute('john','davids'); So I can create (name,surname) from array, and (?,?) as well, but cannot create 'john','davids' as arguments for execute function. thanks

Niet the Dark Absol Over a year ago

@ftom2 Try passing an array to echo. By your logic it should be the same as passing the individual values.

Tomer Over a year ago

@Kolink - I am assuming write() is a function he wrote, not a built in function, and as he mentioned it accepts many arguments, so it seems better to just send an array and if needed change the functionality a bit to accommodate to it.

Davit Over a year ago

That's how I managed to do this: $stmt = $this->dbi->prepare($sql); $stmt = call_user_func_array(array($stmt, "execute"), $args);

Collectives™ on Stack Overflow

PHP How to pass all array's values as different arguments to a function?

2 Answers 2

1 Comment

5 Comments

Your Answer

Hot Network Questions

Collectives™ on Stack Overflow

2 Answers 2

1 Comment

5 Comments

Your Answer

Sign up or log in

Post as a guest

Related