C for loop through array with pointers

Question

I'm new to C but I have experience in Java and Android. I have a problem in my for loop. It will never end and just go on and on.

char entered_string[50];
char *p_string = NULL;

gets( entered_string );

for( p_string = entered_string; p_string != '\0'; p_string++ ){
    //....
}

I know that gets is unsafe, not recommended and deprecated but according to my specs I have to use it. I want to loop through each element by using pointers.

Cornstalks · Accepted Answer · 2012-11-17 19:49:35Z

12

Your test should be *p_string != '\0';

p_string is a pointer, and your loop is checking if the pointer is != '\0'. You're interested in if the value is != '\0', and to get the value out of a pointer you have to dereference it with *.

answered Nov 17, 2012 at 19:49

Cornstalks

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1 Comment

TutenStain Over a year ago

I have tried to solve this problem for a while now. Works perfectly Thank you! It takes time to grasp pointers after coming from 2 years java programming w/o using references on daily basis.

Diizzy · Accepted Answer · 2015-01-19 19:30:46Z

3

    char str[] = "54321"; 
    char *p;  
    p = str;   
    for (p; *p != '\0';++p)
    {
         printf("%s \n",p);
    }

Output:
54321
4321
321
21
1

answered Jan 19, 2015 at 19:30

Diizzy

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Comments

Nikolai Fetissov · Accepted Answer · 2012-11-17 19:50:14Z

1

It should be *p_string != '\0' for the condition - you need to de-reference the pointer.

answered Nov 17, 2012 at 19:50

Nikolai Fetissov

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