type object 'datetime.datetime' has no attribute 'datetime'

Datetime is a module that allows for handling of dates, times and datetimes (all of which are datatypes). This means that datetime is both a top-level module as well as being a type within that module. This is confusing.

Your error is probably based on the confusing naming of the module, and what either you or a module you're using has already imported.

>>> import datetime
>>> datetime
<module 'datetime' from '/usr/lib/python2.6/lib-dynload/datetime.so'>
>>> datetime.datetime(2001,5,1)
datetime.datetime(2001, 5, 1, 0, 0)

But, if you import datetime.datetime:

>>> from datetime import datetime
>>> datetime
<type 'datetime.datetime'>
>>> datetime.datetime(2001,5,1) # You shouldn't expect this to work 
                                # as you imported the type, not the module
Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
AttributeError: type object 'datetime.datetime' has no attribute 'datetime'
>>> datetime(2001,5,1)
datetime.datetime(2001, 5, 1, 0, 0)

I suspect you or one of the modules you're using has imported like this: from datetime import datetime.

You should really import the module into its own alias.

import datetime as dt
my_datetime = dt.datetime(year, month, day)

The above has the following benefits over the other solutions:

• Calling the variable my_datetime instead of date reduces confusion since there is already a date in the datetime module (datetime.date).
• The module and the class (both called datetime) do not shadow each other.

You should use

date = datetime(int(year), int(month), 1)

Or change

from datetime import datetime

to

import datetime

If you have used:

from datetime import datetime

Then simply write the code as:

date = datetime(int(year), int(month), 1)

But if you have used:

import datetime

then only you can write:

date = datetime.datetime(int(2005), int(5), 1)

I run into the same error maybe you have already imported the module by using only import datetime so change from datetime import datetime to only import datetime. It worked for me after I changed it back.

import time
import datetime
from datetime import date,timedelta

You must have imported datetime from datetime.

Avoid to write:

from datetime import datetime
datetime.datetime.function()

Solution No. 1:

import datetime
datetime.datetime.function()

Solution No. 2:

from datetime import datetime
datetime.function()

I found this to be a lot easier

from dateutil import relativedelta
relativedelta.relativedelta(end_time,start_time).seconds

You can simply run the below command.

import datetime

datetime.fromtimestamp(details.start_date).strftime("%Y-%m-%d %H:%M:%S")

from datetime import datetime
import time
from calendar import timegm
d = datetime.utcnow()
d = d.strftime("%Y-%m-%dT%H:%M:%S.%fZ")
utc_time = time.strptime(d,"%Y-%m-%dT%H:%M:%S.%fZ")
epoch_time = timegm(utc_time)

delete one datetime from:

date = datetime.datetime(int(year), int(month), 1)

and you get this:

date = datetime(int(year), int(month), 1)

you already imported the first one with this:

from datetime import datetime

so its redundant.

I tried :

import datetime 
from datetime import timedelta

and it worked somewhat

You should use dt.datetime instead of datetime.datetime. It works very well like in the example below:

    import datetime as dt
    from datetime import datetime,timedelta


    string_date1="2023-11-22"
    date1=dt.datetime.strptime(string_date1, "%Y-%m-%d").date()
    print(date1)
    string_added_days="14";added_days=dt.timedelta(days=int(string_added_days))
    print(added_days)
    date_in_future=date1+added_days
    print(date_in_future)

from datetime import datetime, timedelta, timezone

print(datetime.today()  - datetime.timedelta(days=int(15)))

This will give you error like type object 'datetime.datetime' has no attribute 'timedelta'.

Use below will work:

from datetime import datetime, timedelta, timezone

print(datetime.today()  - timedelta(days=int(15)))