JavaScript: Searching for a string inside a string

Question

I need to find a regular expression that would be able to work around an issue I am having.

Query: barfly london

Should match: Camden Barfly, 49 Chalk Farm Road, London, NW1 8AN

I've tried many, many regex's for this, but none have worked so far. I am considering that maybe I will need to split the search into two separate queries for it to work.

Could anyone point me in the right direction? I'm a bit new to this area.

Is the order of the words in the query to be preserved in the subject string? — palindrom
– palindrom, Commented Jul 29, 2009 at 13:35
no the order of words does not matter, as long as they are all present — tombazza
– tombazza, Commented Jul 29, 2009 at 14:20

mwilcox · Accepted Answer · 2009-07-29 12:51:16Z

3

Try this:

var r = /barfly|london/gi
str = "Camden Barfly, 49 Chalk Farm Road, London, NW1 8AN"
alert(str.match(r).length>1)

answered Jul 29, 2009 at 12:51

mwilcox

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2 Comments

tombazza Over a year ago

this is pretty darn close to what I need, the only problem is it must match all not any

mwilcox Over a year ago

I stand by my solution because the final test of the length is to ensure there are at least two matches. It would only fail in edge cases, like living on Barflybarfly road in Manchester.

Dominic Rodger · Accepted Answer · 2009-07-29 12:51:39Z

2

I'd suggest not using regexs if you want to search for two string literals, and instead use normal string searching twice:

var test="Camden Barfly, 49 Chalk Farm Road, London, NW1 8AN"
if ((test.indexOf("Barfly") != -1) && (test.indexOf("London") != -1)) {
   alert("Matched!");
}

If you're not concerned about case-sensitivity, then you can just lowercase/uppercase your test string and your string literals accordingly.

answered Jul 29, 2009 at 12:51

Dominic Rodger

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Comments

Makram Saleh · Accepted Answer · 2009-07-29 13:24:54Z

Check this:

var my_text = "Camden Barfly, 49 Chalk Farm Road, London, NW1 8AN, london again for testing"
var search_words = "barfly london";

String.prototype.highlight = function(words_str)
{
    var words = words_str.split(" ");
    var indicies = [];
    var last_index = -1;
    for(var i=0; i<words.length; i++){
        last_index = this.toLowerCase().indexOf(words[i], last_index);
        while(last_index != -1){
            indicies.push([last_index, words[i].length]);
            last_index = this.toLowerCase().indexOf(words[i], last_index+1);
        }

    }
    var hstr = "";
    hstr += this.substr(0, indicies[0][0]);
    for(var i=0; i<indicies.length; i++){
        hstr += "<b>"+this.substr(indicies[i][0], indicies[i][1])+"</b>";
        if(i < indicies.length-1) {
            hstr += this.substring(indicies[i][0] + indicies[i][1], indicies[i+1][0]);
        }
    }
    hstr += this.substr(indicies[indicies.length-1][0]+indicies[indicies.length-1][1], this.length);
    return hstr;
}

alert(my_text.highlight(search_words));
// outputs: Camden <b>Barfly</b>, 49 Chalk Farm Road, <b>London</b>, NW1 8AN, <b>london</b> again for testing

palindrom · Accepted Answer · 2009-07-29 13:50:11Z

0

theString.match( new RegExp( query.replace( ' ', '\b.*\b' ), 'i' ) )

answered Jul 29, 2009 at 13:50

palindrom

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Comments

kuester2000 · Accepted Answer · 2009-10-20 11:59:37Z

0

Dominic's solution without case sensitivity. This is what I needed for my project.

var test="Camden Barfly, 49 Chalk Farm Road, London, NW1 8AN";
if ((test.toLowerCase().indexOf("barfly") != -1) && (test.toLowerCase().indexOf("london") != -1)) {
    alert("Matched");
}
else {
    alert("Not matched");
}

edited Oct 20, 2009 at 11:59

answered Oct 20, 2009 at 11:35

kuester2000

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