How do you find Min & Max of a property in an array of objects in Javascript

Question

I have the following javascript object:

Person1.Name = "John";
Person1.Age = 12;

Person2.Name = "Joe";
Person2.Age = 5;

I then have an array of persons, how do I find the Min/Max based on a persons age?

Any solution in Javascript or Jquery is acceptable.

your help is much appreciated.

possible duplicate of jQuery min/max property from array of elements — Andrzej Doyle
– Andrzej Doyle, Commented Aug 16, 2012 at 10:23
possible duplicate of Compare JavaScript Array of Objects to Get Min / Max — Felix Kling
– Felix Kling, Commented Aug 16, 2012 at 10:23
@AnthonyGrist - I tried manually iterating through and finding Min/Max however Kooilnc's solution was the elegant solution I was after. :-) — MaYaN
– MaYaN, Commented Aug 16, 2012 at 10:37

KooiInc · Accepted Answer · 2017-03-21 10:04:52Z

24

Say your array looks like this:

var persons = [{Name:"John",Age:12},{Name:"Joe",Age:5}];

then you can:

var min = Math.min.apply(null, persons.map(function(a){return a.Age;}))
   ,max = Math.max.apply(null, persons.map(function(a){return a.Age;}))

[Edit] Added ES2015 method:

const minmax = (someArrayOfObjects, someKey) => {
  const values = someArrayOfObjects.map( value => value[someKey] );
  return {
      min: Math.min.apply(null, values), 
      max: Math.max.apply(null, values)
    };
};

console.log(
  minmax( 
    [ {Name: "John", Age: 12},
      {Name: "Joe", Age: 5},
      {Name: "Mary", Age: 3},
      {Name: "James sr", Age: 93},
      {Name: "Anne", Age: 33} ], 
    'Age') 
);

edited Mar 21, 2017 at 10:04

answered Aug 16, 2012 at 10:27

KooiInc

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Comments

Linus Thiel · Accepted Answer · 2012-08-16 10:23:10Z

1

First you sort the array with a custom sorting function:

var sorted = persons.sort(function(a, b) {
  if(a.Age > b.Age) return 1;
  else if(a.Age < b.Age) return -1;
  else return 0;
});

Then you can just take the first and last:

var min = sorted[0],
    max = sorted[sorted.length - 1];

answered Aug 16, 2012 at 10:23

Linus Thiel

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