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Answer was wrong, Math.floor didn't round to nearest multiple, but the nearest smaller multiple.

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edit approved Jun 21, 2018 at 6:44

You can do something like this

int gridCubeWidth = 16, gridCubeHeight = 16;

cube.Position.X = Math.Floorround(cube.Position.X / gridCubeWidth) * gridCubeWidth;
cube.Position.Y = Math.Floorround(cube.Position.Y / gridCubeHeight) * gridCubeHeight;

This basically rounds the X and Y positions to the nearest multiple of the cube dimensions. Then scales it by the cube dimensions to get the uniform position.

You can do something like this

int gridCubeWidth = 16, gridCubeHeight = 16;

cube.Position.X = Math.Floor(cube.Position.X / gridCubeWidth) * gridCubeWidth;
cube.Position.Y = Math.Floor(cube.Position.Y / gridCubeHeight) * gridCubeHeight;

This basically rounds the X and Y positions to the nearest multiple of the cube dimensions. Then scales it by the cube dimensions to get the uniform position.

You can do something like this

int gridCubeWidth = 16, gridCubeHeight = 16;

cube.Position.X = Math.round(cube.Position.X / gridCubeWidth) * gridCubeWidth;
cube.Position.Y = Math.round(cube.Position.Y / gridCubeHeight) * gridCubeHeight;

This basically rounds the X and Y positions to the nearest multiple of the cube dimensions. Then scales it by the cube dimensions to get the uniform position.

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answered Jul 28, 2012 at 3:59

Austin Brunkhorst

You can do something like this

int gridCubeWidth = 16, gridCubeHeight = 16;

cube.Position.X = Math.Floor(cube.Position.X / gridCubeWidth) * gridCubeWidth;
cube.Position.Y = Math.Floor(cube.Position.Y / gridCubeHeight) * gridCubeHeight;

This basically rounds the X and Y positions to the nearest multiple of the cube dimensions. Then scales it by the cube dimensions to get the uniform position.